zip extract file

hi all,

I try to exrtact a file in a zip archive but there is an error that I could not find the mistake. Please help me

FindFileRes = zipFindFile(ArchiveName, FindFile,False)
IF FindFileRes > 0 THEN
ExtractErrorCode = zipExtractFile(ArchiveName,FindFileRes,"C:\temp")
The file is found, andthe error is "invalid path" but the part name is correct

Hello Emirhan,

The pathname should end with a backslash: 'C:\temp\'.

HTH.

I used the pathname with backslash but, it extract the file with its directory, I need to extract only the selected file, I don't need file with its directory folder

Hello Emirhan,

I don't know if it is possible, but the constant zipNone extracts the file in the directory without it's original tree-structure. Perhaps you can use:

ExtractErrorCode = zipExtractFile(ArchiveName,FindFileRes,"C:\temp"+zipNone)

HTH.