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String Handling

Posted by Mark 
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Mark
String Handling
April 03, 2008 10:45AM
Hi, I am a newbie with Windev so please excuse my ignorance, but I need to solve a problem & wondered whether anybody could help.

I have a string which contains the following data:-

mystring = "GB1234567890"

I need to determine how many alpha characters are contained in mystring, can anyone
advise how I would achieve this?

Tks
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Paulo Oliveira
Re: String Handling
April 03, 2008 01:08PM
if you only nedd the number of char. use length.
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Stefan Bentvelsen
Re: String Handling
April 03, 2008 02:13PM
Hi Mark,

the following code counts the alpha characters. The info() results 2 in this case.
Attention, it only counts uppercase characters now!

sHlp is string="AB1234567890"
i,j is int

FOR i=1 TO Length(sHlp)
IF sHlp[[i]]>="A" _AND_ sHlp[[i]]<="Z" THEN j++
END
Info(j)

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Leo Voet
Re: String Handling
April 03, 2008 02:28PM
IF sHlp[[i]]>="A" _AND_ sHlp[[i]]<="Z" THEN j++
A lesser known, but quicker way to code :

IF "A"<= sHlp[[i]] <= "Z" THEN j++


... and it performance is (slightly) faster as well.

Leo.
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Mark
Re: String Handling
April 03, 2008 03:23PM
Sefan,

Thanks very much, just the job!

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Mark
Re: String Handling
April 03, 2008 03:25PM
Leo,

Thanks also, excellent neat that it's just one line of code!
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Marc De Swert
Re: String Handling
April 03, 2008 04:02PM
or...
you can handle lower, upeer and numbers at the same time

sHlp is string="AB1234567DE Rs e890"
i,j,k are int
sTemp is int


FOR i=1 TO Length(sHlp)
stemp = Asc(sHlp[[i]])
IF ((stemp >= 65 AND stemp <= 90) OR (stemp >= 97 AND stemp <= 122)) THEN j++
IF (stemp >= 48 AND stemp <= 57) THEN k++
END
Info("ALPHA: " + j + " NUMB: " + K)


Greetings, Marc.
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Rich
Re: String Handling
April 03, 2008 07:06PM
Why not just use IF NOT IsNumeric(sHlp[[i]] ) then k++
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Marc De Swert
Re: String Handling
April 04, 2008 07:49AM
if you only test on "Not is numeric" then the space(s) and the / are also counted, the question was to count Alpha, in the example here you will count those chars in the result

sHlp is string="AB1234567DE/ Rs e890"
i,j,k , ni are int
sTemp is int


FOR i=1 TO Length(sHlp)
stemp = Asc(sHlp[[i]])
IF ((stemp >= 65 AND stemp <= 90) OR (stemp >= 97 AND stemp <= 122)) THEN j++
IF (stemp >= 48 AND stemp <= 57) THEN k++
IF NOT IsNumeric(sHlp[[i]]) THEN ni++
END
Info(" NotNumeric : " + ni + " ALPHA: " + j + " NUMB: " + K)

:xcool:
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Rich
Re: String Handling
April 04, 2008 01:15PM
Marc,

Ok, I missed the point that there could be spaces and other characters in the string.sad smiley

The original question had just alpha and numeric.

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Marc De Swert
Re: String Handling
April 04, 2008 02:19PM
No problemo

have a nice weekend

:xcool:
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Carlo Hermus
Re: String Handling
April 06, 2008 07:48PM
Hi,

Why not 

i, j is int
mystring = "Gb1234567890" 

FOR i = 1 TO Length(mystring )
	IF MatchRegularExpression(mystring [[i]], "[A-Za-z]") THEN j++
END
Info("Total letters in string: "+j)
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Mark
Re: String Handling
April 07, 2008 10:38AM
Carlo,

Thanx for that suggestion, I'll try that out also.

Mark
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Marc
Re: String Handling
April 07, 2008 10:39AM
Marc,

Thanx very much for your suggestion.

Mark
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